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What is the longest wavelength of light to which a single photon could ionize an aluminum atom? Chemistry The Periodic Table Periodic Trends in Ionization Energy. Use the above equation to calculate the frequency of a photon that carries enough energy to ionize a single atom of aluminium.Any radiation less than 242nm like Gamma and X-Rays can break this bond. Infrared radiation has the longest wavelength of those listed. Refer to the related link below for an illustration of the Radio Waves have the longest wavelength of any EM radiation, so they usually have the least energy.the bond energy is the energy required to break the C-F bond. CF4 = 4 C-F bonds 1/4CF4 = 1 C-F bond. as you can see the second one is for 1 bond which is what we want. the other 2 are bond formation. don't quote me on this though. 1.What is the longest wavelength of radiation that possesses the necessary energy to break the bond? Light of wavelength 3.34 × 10−6 m can excite molecular vibrations in HCl. What is the energy of a photon with this wavelength?A minimum energy of 242 kJ/mol isrequired to break the… What isthe longest wavelength of radiation that possesses the necessaryenergy to break the bond? What type of electromagneticradiation is this?

What is the longest wavelength of radiation that possesses the...

Energy is calculated by molecule dividing energy by mole by Avogadro's number (6.022*10^23) 941kJ=9.41*10^5 J so energy by molecule E= 9.41*10^5/6.022*10^23=1.563 She took before and after pictures each time to monitor her progress. What would be the CONTROL experiment for Jenny?What is the longest wavelength of radiation that possesses the necessary energy to break the bond? What type of electromagnetic radiation is this? 6.19 A diode laser emits at a wavelength of 987 nm. All of its output energy is absorbed in a detector that measures a total energy of 0.52 J over...The energy from radiation can be used to cause the rupture of chemical bonds. A minimum energy of 941 kJ/ mol is required to break the nitrogen-nitrogen bond in N_2. how would i do this?The energy of a photon is related to its wavelength, with longer wavelengths having less energy. Photons with too little or too much energy cannot be The photolysis rate generally depends upon the absorption cross-section of ozone and the number of incident photons at the necessary wavelengths.

What is the longest wavelength of radiation that possesses the...

What's the mean bond energy of the C-F bond? - The Student Room

ecause they carry enough energy to break bonds within the molecules. A typical carbon-carbon bond requires 348 kJ/mol to break. m = 344 x 10^-9 m = 344 nm This is the longest wavelength of radiation that is able to break carbon-carbon bonds.The total energy input or output of a reaction equals the energy released in forming new bonds minus the energy used in breaking the original bonds. A chemical bond holds two atoms together. To break the bond, you have to fight against the bond, like stretching a rubber band until it snaps.Also, EM-radiation radiated by a body falling into a black hole will also redshift into "infinity" at the event horizon. 2) No, the 5 million km is because gravity waves have such a small influence Related Threads on What's the longest wavelength possible? What is the longest wave-lenght of a photon?Outgoing Long-wave Radiation (OLR) is electromagnetic radiation of wavelengths from 3-100 μm emitted from Earth and its atmosphere out to space in the form of thermal radiation. It is also referred to as up-welling long-wave radiation and terrestrial long-wave flux, among others.Generally, radiation with wavelengths much shorter than visible light have enough energy to strip electrons from atoms. Nuclear processes in atoms produce this kind of radiation, which has more Although microwaves have wavelengths too long to be ionizing, the power in microwaves can make...

I calculate the energy by way of molecule dividing energy by mole through Avogadro's quantity (6.022*10^23)

941kJ=9.41*10^5J

so energy by molecule

E= 9.41*10^5/6.022*10^23=1.563*10^-18J

I calculate the wavelength (w) given through E=hc/w

So w= hc/E = 6.6262*10^-34*3*10^8/1.563*10^-18=1.272*10^-7m = 127.2nm

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